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- \begin{frage}[3]
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- Finden Sie $\LoesungsMenge{}_{(x;y)}$:
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- \gleichungZZ{(x-3)(y+6)}{(x-4)(y+3)}{(y-3)(x+6)}{(x-4)(y+3)}
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- $$\LoesungsMenge{}_{(x;y)}=\LoesungsRaumLang{x=1.5 \textrm{ und } y=1.5}$$
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- \platzFuerBerechnungen{10.8}
- \end{frage}
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