phi 2 settimane fa
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2601f79965

11_21_6ZBG24s_pr2_AA1/Lernziele.tex → archiv/24_25_A/11_21_6ZBG24s_pr2_AA1/Lernziele.tex Vedi File


11_21_6ZBG24s_pr2_AA1/Pruefung.tex → archiv/24_25_A/11_21_6ZBG24s_pr2_AA1/Pruefung.tex Vedi File


11_21_6ZBG24s_pr2_AA1/PruefungHeader.tex → archiv/24_25_A/11_21_6ZBG24s_pr2_AA1/PruefungHeader.tex Vedi File


11_21_6ZBG24s_pr2_AA1/PruefungHeader_TRAINER.tex → archiv/24_25_A/11_21_6ZBG24s_pr2_AA1/PruefungHeader_TRAINER.tex Vedi File


11_21_6ZBG24s_pr2_AA1/clean.sh → archiv/24_25_A/11_21_6ZBG24s_pr2_AA1/clean.sh Vedi File


11_21_6ZBG24s_pr2_AA1/dirMake.sh → archiv/24_25_A/11_21_6ZBG24s_pr2_AA1/dirMake.sh Vedi File


12_05_6ZBG24s_pr2_np_AA1/Lernziele.tex → archiv/24_25_A/12_05_6ZBG24s_pr2_np_AA1/Lernziele.tex Vedi File


12_05_6ZBG24s_pr2_np_AA1/Pruefung.tex → archiv/24_25_A/12_05_6ZBG24s_pr2_np_AA1/Pruefung.tex Vedi File


12_05_6ZBG24s_pr2_np_AA1/PruefungHeader.tex → archiv/24_25_A/12_05_6ZBG24s_pr2_np_AA1/PruefungHeader.tex Vedi File


12_05_6ZBG24s_pr2_np_AA1/PruefungHeader_TRAINER.tex → archiv/24_25_A/12_05_6ZBG24s_pr2_np_AA1/PruefungHeader_TRAINER.tex Vedi File


12_05_6ZBG24s_pr2_np_AA1/clean.sh → archiv/24_25_A/12_05_6ZBG24s_pr2_np_AA1/clean.sh Vedi File


12_05_6ZBG24s_pr2_np_AA1/dirMake.sh → archiv/24_25_A/12_05_6ZBG24s_pr2_np_AA1/dirMake.sh Vedi File


+ 1
- 1
aufgaben/alg/grundlagen/faktorisieren/Basis/variable/Ausklammern_Gemeinsame_Faktoren_v1_tals_np.tex Vedi File

@@ -5,7 +5,7 @@
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 \begin{frage}[1]
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   Klammern Sie in der folgenden Differenz den größtmöglichen Faktor aus:
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-  $$7sb^4-14b^6s+ - 7bs + 42b^2s-84bs =   \LoesungsRaumLen{40mm}{7bs\cdot{}(b^3 - 2b^5 -1 + 6b - 14)}$$
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+  $$7sb^4-14b^6s  - 7bs + 42b^2s-84bs =   \LoesungsRaumLen{40mm}{7bs\cdot{}(b^3 - 2b^5 + 6b - 13)}$$
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   \platzFuerBerechnungen{4}
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 \end{frage}

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